Chapter: Circle· Mathematics Part 2 (Geometry)
Answer: AP = 7 cm, BQ = 5 cm, CR = 3 cm
Tangent segments from an external point are congruent: let AP = AR = x, BP = BQ = y, CQ = CR = z.
AB: \(x + y = 12\); BC: \(y + z = 8\); CA: \(z + x = 10\).
Adding: \(2(x + y + z) = 30\) \(\therefore x + y + z = 15\).
\(\therefore x = 15 - 8 = 7\), \(y = 15 - 10 = 5\), \(z = 15 - 12 = 3\).
So AP = 7 cm, BQ = 5 cm, CR = 3 cm.