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Answer: 4. A = 1, B = 0, C = 1

Key idea: from the circuit, \(Y=(A+B)\cdot C\): A and B go to an OR gate, and its output goes to an AND gate with C.

For \(Y=1\) we need \(C=1\) and at least one of A, B equal to 1. Only option 4 (A = 1, B = 0, C = 1) satisfies this. Options 1, 2 and 3 all have \(C=0\), giving \(Y=0\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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