Among the following, the correct order of acidity is :
1. \(HClO_3 < HClO_4 < HClO_2 < HClO\)
2. \(HClO < HClO_2 < HClO_3 < HClO_4\)
3. \(HClO_2 < HClO < HClO_3 < HClO_4\)
4. \(HClO_4 < HClO_2 < HClO < HClO_3\)
1. \(HClO_3 < HClO_4 < HClO_2 < HClO\)
2. \(HClO < HClO_2 < HClO_3 < HClO_4\)
3. \(HClO_2 < HClO < HClO_3 < HClO_4\)
4. \(HClO_4 < HClO_2 < HClO < HClO_3\)
Best answer
Answer: 2. \(HClO < HClO_2 < HClO_3 < HClO_4\)
Key idea: in oxoacids of the same halogen, acidity rises with the number of oxygen atoms (higher oxidation state), because the conjugate base is stabilised by more resonance and a stronger inductive pull.
Oxidation state of Cl: HClO (+1), \(\mathrm{HClO_2}\) (+3), \(\mathrm{HClO_3}\) (+5), \(\mathrm{HClO_4}\) (+7).
So acidity: \(\mathrm{HClO<HClO_2<HClO_3<HClO_4}\), which is option 2. The other options break this order.
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