Skip to content
doubtly

1 answer

Best answer

Answer: 1. 1/8

Key idea: Graham's law, rate of effusion \(\propto 1/\sqrt{M}\).

$$\frac{r_{H_2}}{r_{O_2}}=\sqrt{\frac{32}{2}}=4$$

Both gases start with equal moles and leave the same pin-hole in the same time, so moles escaped are in the ratio of rates. When half of \(\mathrm{H_2}\) has escaped, the fraction of \(\mathrm{O_2}\) escaped is \(\tfrac12\times\tfrac14=\tfrac18\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.