1. L_A=2L_B 2. L_B>L_A 3. L_A>L_B 4. L_A=L_B/2

Answer: 2. L_B>L_A Express angular momentum through kinetic energy: K=L²/2I , so L=√(2IK) . The kinetic energies are equal, so L∝sqrt I . Since I_B>I_A , L_B>L_A . Option (2). The masses m and 2m are not needed.

Topic: Comparison of linear and rotational motion· Rotational Motion

Two rotating bodies A and B of masses m and 2m with moments of inertia I_A and I_B (I_B>I_A) have equal kinetic energy of rotation. If L_A and L_B be their angular momenta respectively, then

1. \(L_A=2L_B\)

2. \(L_B>L_A\)

3. \(L_A>L_B\)

4. \(L_A=\frac{L_B}{2}\)

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Answer: 2. \(L_B>L_A\)

Express angular momentum through kinetic energy: \(K=\dfrac{L^2}{2I}\), so \(L=\sqrt{2IK}\).

The kinetic energies are equal, so \(L\propto\sqrt I\). Since \(I_B>I_A\), \(L_B>L_A\). Option (2). The masses \(m\) and \(2m\) are not needed.

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Two rotating bodies A and B of masses m and 2m with moments of inertia I_A and I_B (I_B>I_A) have equal kinetic energy of rotation. If L_A and L_B be their angular momenta respectively, then

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