In pyrrole [figure: five-membered ring, N1 with H, carbons 2,3,4,5] the electron density is maximum on
In pyrrole [figure: five-membered ring, N1 with H, carbons 2,3,4,5] the electron density is maximum on

1. 3 and 4
2. 2 and 4
3. 2 and 5
4. 2 and 3
In pyrrole [figure: five-membered ring, N1 with H, carbons 2,3,4,5] the electron density is maximum on

1. 3 and 4
2. 2 and 4
3. 2 and 5
4. 2 and 3
Best answer
Answer: 3. 2 and 5
Key idea: in pyrrole the N lone pair is part of the aromatic sextet, so the ring carbons are electron-rich, most of all the carbons next to N.
Resonance places negative charge on C2 and C5 (alpha) more than on C3 and C4, and the alpha carbons give the more stable intermediate for electrophilic attack. So electron density is maximum at 2 and 5, which is option 3.
The key copy we had showed option 2 (2 and 4), which cannot be right as C2 and C4 are not equivalent, so it was corrected.
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