The van't Hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is

1. 1

2. 2

3. 3

4. 0

Doubtly Asked 30 Oct 2026 NEET UG 2016 Phase 2 Practice test neet Save WhatsApp Report

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Answer: 3. 3

Key idea: $i$ equals the number of ions per formula unit on complete dissociation.

$$\mathrm{Ba(OH)_2\rightarrow Ba^{2+}+2OH^-}$$

This gives 3 ions, so $i=3$.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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