1. Carbon family, [Rn] 5f¹⁴6d¹⁰7s²7p² 2. Oxygen family, [Rn] 5f¹⁴6d¹⁰7s²7p⁴ 3. Nitrogen family, [Rn] 5f¹⁴6d¹⁰7s²7p⁶ 4. Halogen family, [Rn] 5f¹⁴6d¹⁰7s²7p⁵

Answer: 1. Carbon family, [Rn] 5f¹⁴6d¹⁰7s²7p² Key idea: element 114 lies in the same group as Pb (Z = 82), one period lower, so its outer shell is 7s² 7p² . Noble gas before it is Rn (Z = 86). Filling order after Rn: 7s² (2) + 5f¹⁴ (14) + 6d¹⁰ (10) = 26 electrons, giving Z = 112. Two more electrons go into 7p: 7p² , so Z = 114. Configuration: [Rn] 5f¹⁴6d¹⁰7s²7p² . Four valence electrons ( ns²np² ) means the carbon family. The p⁴, p⁵, p⁶ options belong to groups 16, 17 and 18.

Topic: Modern periodic law and periodic table, s, p, d, f blocks· Classification of Elements and Periodicity in Properties

The element Z = 114 has been discovered recently. It will belong to which of the following family/group and electronic configuration ?

1. Carbon family, [Rn] \(5f^{14}6d^{10}7s^{2}7p^{2}\)

2. Oxygen family, [Rn] \(5f^{14}6d^{10}7s^{2}7p^{4}\)

3. Nitrogen family, [Rn] \(5f^{14}6d^{10}7s^{2}7p^{6}\)

4. Halogen family, [Rn] \(5f^{14}6d^{10}7s^{2}7p^{5}\)

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Answer: 1. Carbon family, [Rn] \(5f^{14}6d^{10}7s^{2}7p^{2}\)

Key idea: element 114 lies in the same group as Pb (Z = 82), one period lower, so its outer shell is \(7s^2 7p^2\).

Noble gas before it is Rn (Z = 86). Filling order after Rn: \(7s^2\) (2) + \(5f^{14}\) (14) + \(6d^{10}\) (10) = 26 electrons, giving Z = 112. Two more electrons go into 7p: \(7p^2\), so Z = 114.

Configuration: \([Rn]\,5f^{14}6d^{10}7s^27p^2\). Four valence electrons (\(ns^2np^2\)) means the carbon family. The \(p^4, p^5, p^6\) options belong to groups 16, 17 and 18.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The element Z = 114 has been discovered recently. It will belong to which of the following family/group and electronic configuration ?

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