1. HgI₂, I^- 2. HgI₄²⁻, I₃^- 3. Hg₂I₂, I^- 4. HgI₂, I₃^-

Answer: 2. HgI₄²⁻, I₃^- Key idea: HgI₂ dissolves in excess I^- and I₂ dissolves in I^- by complex formation. HgCl₂ + 2I^-→ HgI₂ (red precipitate), then mathrmHgI₂ + 2I^-→ [HgI₄]²⁻ (soluble). I₂ + I^-→ I₃^- . The pair formed is mathrmHgI₄²⁻ and I₃^- .

Topic: General trends, Group 17 and 18· p-Block Elements

HgCl_2 and I_2 both when dissolved in water containing I^- ions the pair of species formed is :

1. \(HgI_2, I^-\)

2. \(HgI_4^{2-}, I_3^-\)

3. \(Hg_2I_2, I^-\)

4. \(HgI_2, I_3^-\)

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Answer: 2. \(HgI_4^{2-}, I_3^-\)

Key idea: \(\mathrm{HgI_2}\) dissolves in excess \(\mathrm{I^-}\) and \(\mathrm{I_2}\) dissolves in \(\mathrm{I^-}\) by complex formation.

\(\mathrm{HgCl_2 + 2I^-\rightarrow HgI_2}\) (red precipitate), then \(\mathrm{HgI_2 + 2I^-\rightarrow [HgI_4]^{2-}}\) (soluble).
\(\mathrm{I_2 + I^-\rightarrow I_3^-}\).

The pair formed is \(\mathrm{HgI_4^{2-}}\) and \(\mathrm{I_3^-}\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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HgCl_2 and I_2 both when dissolved in water containing I^- ions the pair of species formed is :

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