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Answer: 1. \(S_4O_6^{2-}, S_2O_3^{2-}\)

Key idea: draw the structures.

  • \(\mathrm{S_4O_6^{2-}}\) (tetrathionate): has an S-S bond in the chain \(\mathrm{O_3S-S-S-SO_3}\).
  • \(\mathrm{S_2O_3^{2-}}\) (thiosulphate): one S is attached to the central S, giving an S-S bond.
  • \(\mathrm{S_2O_7^{2-}}\) and \(\mathrm{S_2O_8^{2-}}\) have S-O-S and O-O bridges, with no S-S bond.

So both ions in option 1 contain an S-S bond.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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