The genotypes of a Husband and Wife are I^AI^B and I^Ai.Among the blood types of their children, how many different genotypes and phenotypes are possible ?

1. 3 genotypes ; 4 phenotypes

2. 4 genotypes ; 3 phenotypes

3. 4 genotypes ; 4 phenotypes

4. 3 genotypes ; 3 phenotypes

Doubtly Asked 30 Oct 2026 NEET UG 2017 Practice test neet Save WhatsApp Report

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Answer: 2. 4 genotypes ; 3 phenotypes

Write the Punnett cross of the parents and count the distinct genotypes and blood groups.

Gametes: \(I^A, I^B\) from the husband; \(I^A, i\) from the wife.
Children: \(I^AI^A\), \(I^Ai\), \(I^AI^B\), \(I^Bi\) = 4 genotypes.
Phenotypes: \(I^AI^A\) and \(I^Ai\) are both group A; \(I^AI^B\) is AB; \(I^Bi\) is B = 3 phenotypes.

So 4 genotypes and 3 phenotypes. The other options miscount either genotypes or the fact that \(I^A\) is dominant over \(i\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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