1. 2.83×10⁻⁸ T 2. 0.70×10⁻⁸ T 3. 4.23×10⁻⁸ T 4. 1.41×10⁻⁸ T

Answer: 1. 2.83×10⁻⁸ T Key idea: peak value =sqrt2× rms value, and B₀=E₀/c . E₀=6sqrt2=8.49 V/m. B₀=8.49/3×10⁸=2.83×10⁻⁸ T.

In an electromagnetic wave in free space the root mean square value of the electric field is E_rms = 6 V/m. The peak value of the magnetic field is :

1. \(2.83\times10^{-8}\) T

2. \(0.70\times10^{-8}\) T

3. \(4.23\times10^{-8}\) T

4. \(1.41\times10^{-8}\) T

Doubtly Asked 30 Oct 2026 NEET UG 2017 Practice test neet Save WhatsApp Report

Best answer

Answer: 1. \(2.83\times10^{-8}\) T

Key idea: peak value \(=\sqrt2\times\) rms value, and \(B_0=E_0/c\).

\(E_0=6\sqrt2=8.49\) V/m.

\(B_0=\dfrac{8.49}{3\times10^8}=2.83\times10^{-8}\) T.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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