1. 5 m/s ² 2. - 4 m/s ² 3. - 8 m/s ² 4. 0

Answer: 2. - 4 m/s ² Key idea: acceleration components are second derivatives of position. a_x=d²x/dt²=-4 m/s ² , a_y=d²y/dt²=0 . Acceleration is constant, so at t=2 s it is -4 m/s ² .

Topic: Frame of reference, motion in a straight line, speed and velocity· Kinematics

The x and y coordinates of the particle at any time are x = 5t - 2t^2 and y = 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t = 2s is :

1. 5 m/s\(^2\)

2. \(-\)4 m/s\(^2\)

3. \(-\)8 m/s\(^2\)

4. 0

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Answer: 2. \(-\)4 m/s\(^2\)

Key idea: acceleration components are second derivatives of position.

\(a_x=\dfrac{d^2x}{dt^2}=-4\) m/s\(^2\), \(a_y=\dfrac{d^2y}{dt^2}=0\).

Acceleration is constant, so at \(t=2\) s it is \(-4\) m/s\(^2\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The x and y coordinates of the particle at any time are x = 5t - 2t^2 and y = 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t = 2s is :

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