1. 40 Ω 2. 250 Ω 3. 25 Ω 4. 500 Ω

Answer: 2. 250 Ω Current sensitivity I_s=θ/I and voltage sensitivity V_s=θ/V . Since V=IG , V_s=I_s/G . G=I_s/V_s=5\ div/mA/20\ div/V=frac5\ div/10⁻³A20\ div/V=250\ Ω

Topic: Torque on current loop, moving coil galvanometer, conversion to ammeter and voltmeter· Magnetic Effects of Current and Magnetism

Current sensitivity of a moving coil galvanometer is 5 div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V. The resistance of the galvanometer is

1. 40 $\Omega$

2. 250 $\Omega$

3. 25 $\Omega$

4. 500 $\Omega$

Doubtly Asked 30 Oct 2026 NEET UG 2018 Practice test neet Save WhatsApp Report

1 answer

Best answer

Answer: 2. 250 $\Omega$

Current sensitivity $I_s=\dfrac{\theta}{I}$ and voltage sensitivity $V_s=\dfrac{\theta}{V}$. Since $V=IG$, $V_s=\dfrac{I_s}{G}$.

$$G=\frac{I_s}{V_s}=\frac{5\ \mathrm{div/mA}}{20\ \mathrm{div/V}}=\frac{5\ \mathrm{div}/10^{-3}\mathrm{A}}{20\ \mathrm{div/V}}=250\ \Omega$$

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

Was this answer helpful?

Current sensitivity of a moving coil galvanometer is 5 div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V. The resistance of the galvanometer is

1 answer

Your answer