1. BeH ₂ < CaH ₂ < BaH ₂ 2. BeH ₂ < BaH ₂ < CaH ₂ 3. CaH ₂ < BeH ₂ < BaH ₂ 4. BaH ₂ < BeH ₂ < CaH ₂

Among CaH_2, BeH_2, BaH_2, the order of ionic character is

1. BeH\(_2\) < CaH\(_2\) < BaH\(_2\)

2. BeH\(_2\) < BaH\(_2\) < CaH\(_2\)

3. CaH\(_2\) < BeH\(_2\) < BaH\(_2\)

4. BaH\(_2\) < BeH\(_2\) < CaH\(_2\)

Doubtly Asked 30 Oct 2026 NEET UG 2018 neet Save WhatsApp Report

Best answer

Answer: 1. BeH\(_2\) < CaH\(_2\) < BaH\(_2\)

Ionic character of a metal hydride increases with the electropositive (metallic) character of the metal, which increases down group 2.

Be is small and highly polarising, so \(\mathrm{BeH_2}\) is covalent; Ca is more electropositive; Ba is the most. Order: \(\mathrm{BeH_2

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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