Topic: Balancing redox reactions· Redox Reactions and Electrochemistry

For the redox reactionMnO_4^- + C_2O_4^2- + H^+ Mn^2+ + CO_2 + H_2Othe correct coefficients of the reactants for the balanced equation are(columns: MnO_4^-, C_2O_4^2-, H^+)

1. 16, 5, 2

2. 2, 16, 5

3. 2, 5, 16

4. 5, 16, 2

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Answer: 3. 2, 5, 16

Balance by the ion-electron method.

Reduction: \(\mathrm{MnO_4^-+8H^++5e^-\to Mn^{2+}+4H_2O}\). Oxidation: \(\mathrm{C_2O_4^{2-}\to2CO_2+2e^-}\).

Multiply the first by 2 and the second by 5 to balance 10 electrons: \(\mathrm{2MnO_4^-+5C_2O_4^{2-}+16H^+\to2Mn^{2+}+10CO_2+8H_2O}\). The coefficients are 2, 5, 16.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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For the redox reactionMnO_4^- + C_2O_4^2- + H^+ Mn^2+ + CO_2 + H_2Othe correct coefficients of the reactants for the balanced equation are(columns: MnO_4^-, C_2O_4^2-, H^+)

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