Which one is a wrong statement ? 1. Total orbital angular momentum of electron in 's' orbital is equal to zero. 2. The electronic configuration of N atom is 1s ² 2s ² 2p _x¹ 2p _y¹ 2p _z¹ shown as orbital box diagram: 1s [up down], 2s [up down], 2p [up][up][down] 3. An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers. 4. The value of m for d _z² is zero.

Topic: Quantum numbers and shapes of s, p, d orbitals· Atomic Structure

Which one is a wrong statement ?

orbital box diagram for N atom in option 2

1. Total orbital angular momentum of electron in 's' orbital is equal to zero.

2. The electronic configuration of N atom is
1s\(^2\) 2s\(^2\) 2p\(_x^1\) 2p\(_y^1\) 2p\(_z^1\) shown as orbital box diagram: 1s [up down], 2s [up down], 2p [up][up][down]

3. An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers.

4. The value of m for d\(_{z^2}\) is zero.

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Answer: 2. The electronic configuration of N atom is1s\(^2\) 2s\(^2\) 2p\(_x^1\) 2p\(_y^1\) 2p\(_z^1\) shown as orbital box diagram: 1s [up down], 2s [up down], 2p [up][up][down]

Option 1 is true: for an s orbital \(l=0\), so orbital angular momentum is zero. Option 3 is true: an orbital needs \(n,l,m\), an electron also needs \(s\). Option 4 is true: \(m=0\) for \(d_{z^2}\).

Option 2 shows the three 2p electrons with the third spin opposite to the other two, which breaks Hund's rule (all three should be parallel). This is the wrong statement (option 2).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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Which one is a wrong statement ?

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