A force F = 20 + 10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is :

1. 30 J

2. 5 J

3. 25 J

4. 20 J

Doubtly Asked 30 Oct 2026 NEET UG 2019 Practice test neet Save WhatsApp Report

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Answer: 3. 25 J

Work done by a variable force is \(W=\int F\,dy\).

\(W=\int_0^1(20+10y)\,dy=\left[20y+5y^2\right]_0^1=20+5=25\) J.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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