1. increases as r increases for r R 2. zero as r increases for r R 3. zero as r increases for r R 4. decreases as r increases for r R

Answer: 2. zero as r increases for r R For a uniformly charged hollow sphere, by Gauss's law: Inside ( r Outside ( r>R ): E=1/4πε₀Q/r² , which decreases as r increases. This matches option 2 (the wording \"zero as r increases\" means it stays zero inside).

Topic: Electric flux and Gauss's law applications· Electrostatics

A hollow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre :

1. increases as r increases for r < R and for r > R

2. zero as r increases for r < R, decreases as r increases for r > R

3. zero as r increases for r < R, increases as r increases for r > R

4. decreases as r increases for r < R and for r > R

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Answer: 2. zero as r increases for r < R, decreases as r increases for r > R

For a uniformly charged hollow sphere, by Gauss's law:

Inside (\(r
Outside (\(r>R\)): \(E=\dfrac{1}{4\pi\epsilon_0}\dfrac{Q}{r^2}\), which decreases as \(r\) increases.

This matches option 2 (the wording \"zero as r increases\" means it stays zero inside).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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A hollow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre :

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