1. 2 V 2. 0.2 V 3. 2×10⁻³ V 4. 0.02 V

Answer: 4. 0.02 V The coil starts perpendicular to the field (flux =NBA ) and, after rotating 90^° , lies parallel to it (flux zero). ε=Δφ/Δ t=NBA/t=dfrac800×5×10⁻⁵×0.050.1=dfrac2×10⁻³0.1=0.02 V.

Topic: Faraday's law, induced emf and current· Electromagnetic Induction and Alternating Currents

A 800 turn coil of effective area 0.05 m^2 is kept perpendicular to a magnetic field 5×10^-5 T. When the plane of the coil is rotated by 90^° around any of its coplanar axis in 0.1 s, the emf induced in the coil will be :

1. 2 V

2. 0.2 V

3. \(2\times10^{-3}\) V

4. 0.02 V

Doubtly Asked 30 Oct 2026 NEET UG 2019 Practice test neet Save WhatsApp Report

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Answer: 4. 0.02 V

The coil starts perpendicular to the field (flux \(=NBA\)) and, after rotating \(90^\circ\), lies parallel to it (flux zero).

\(\varepsilon=\dfrac{\Delta\phi}{\Delta t}=\dfrac{NBA}{t}=\dfrac{800\times5\times10^{-5}\times0.05}{0.1}=\dfrac{2\times10^{-3}}{0.1}=0.02\) V.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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A 800 turn coil of effective area 0.05 m^2 is kept perpendicular to a magnetic field 5×10^-5 T. When the plane of the coil is rotated by 90^° around any of its coplanar axis in 0.1 s, the emf induced in the coil will be :

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