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Answer: 1. 5f > 6p > 5p > 4d

Orbital energy in a many-electron atom follows the \((n+l)\) rule; if \((n+l)\) is equal, the orbital with lower \(n\) has lower energy.

Orbitaln + l
4d4 + 2 = 6
5p5 + 1 = 6
6p6 + 1 = 7
5f5 + 3 = 8

So 5f (8) is highest, then 6p (7), then 5p and 4d (both 6; 4d has the lower n so it is lower). Decreasing order: 5f > 6p > 5p > 4d, option (1).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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