A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is :

1. n

2. 2n

3. 3n

4. 4n

Doubtly Asked 30 Oct 2026 NEET UG 2021 Practice test neet Save WhatsApp Report

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Best answer

Answer: 2. 2n

Key idea: potential energy depends on \(x^2\), so it repeats twice per oscillation.

\(x = A\sin\omega t \Rightarrow U=\tfrac12 kx^2=\tfrac12 kA^2\sin^2\omega t=\tfrac14 kA^2(1-\cos 2\omega t)\)

The energy varies with angular frequency \(2\omega\), so its frequency is \(2n\). Option 2.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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