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Topic: Composition and size of nucleus, atomic masses· Atoms and Nuclei

A radioactive nucleus ^A_ZX undergoes spontaneous decay in the sequence^A_ZX → _Z-1B → _Z-3C → _Z-2D, where Z is the atomic number of element X. The possible decay particles in the sequence are :

1. \(\alpha, \beta^-, \beta^+\)

2. \(\alpha, \beta^+, \beta^-\)

3. \(\beta^+, \alpha, \beta^-\)

4. \(\beta^-, \alpha, \beta^+\)

1 answer

Best answer

Answer: 3. \(\beta^+, \alpha, \beta^-\)

Key idea: \(\alpha\) decay lowers Z by 2; \(\beta^-\) raises Z by 1; \(\beta^+\) lowers Z by 1.

  1. \(Z\to Z-1\): \(\beta^+\).
  2. \(Z-1\to Z-3\): \(\alpha\).
  3. \(Z-3\to Z-2\): \(\beta^-\).

Sequence \(\beta^+,\alpha,\beta^-\): option 3.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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