Topic: Reactance, impedance, LCR series circuit, resonance· Electromagnetic Induction and Alternating Currents

An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance 'R' are connected in series to an ac source of potential difference 'V' volts as shown in figure.Potential difference across L, C and R is 40 V, 10 V and 40 V, res…

An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance 'R' are connected in series to an ac source of potential difference 'V' volts as shown in figure.

Potential difference across L, C and R is 40 V, 10 V and 40 V, respectively. The amplitude of current flowing through LCR series circuit is \(10\sqrt{2}\) A. The impedance of the circuit is :

series LCR circuit with ac source, voltages 40 V, 10 V, 40 V

1. \(4\sqrt{2}\ \Omega\)

2. \(5/\sqrt{2}\ \Omega\)

3. \(4\ \Omega\)

4. \(5\ \Omega\)

Doubtly Asked 30 Oct 2026 NEET UG 2021 Practice test neet Save WhatsApp Report

1 answer

Best answer

Answer: 4. \(5\ \Omega\)

Key idea: voltages in series LCR add as phasors: \(V=\sqrt{V_R^2+(V_L-V_C)^2}\), and \(Z=V/I\) with both in the same (rms) form.

\(V=\sqrt{40^2+(40-10)^2}=50\) V

Current amplitude \(10\sqrt2\) A gives rms current \(10\) A, and the marked voltages are rms values, so \(Z=\dfrac{50}{10}=5\ \Omega\). Option 4.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

Was this answer helpful?

An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance 'R' are connected in series to an ac source of potential difference 'V' volts as shown in figure.Potential difference across L, C and R is 40 V, 10 V and 40 V, res…

1 answer

Your answer