1. 201.28 S cm ² mol ⁻¹ 2. 390.71 S cm ² mol ⁻¹ 3. 698.28 S cm ² mol ⁻¹ 4. 540.48 S cm ² mol ⁻¹

Answer: 2. 390.71 S cm ² mol ⁻¹ Key idea: Kohlrausch's law of independent migration of ions. Lambda^°(CH₃COOH)=Lambda^°(CH₃COONa)+Lambda^°(HCl)-Lambda^°(NaCl) =91.0+426.16-126.45=390.71\ mathrmS cm² mol⁻¹ .

Topic: Kohlrausch's law and applications· Redox Reactions and Electrochemistry

The molar conductance of NaCl, HCl and CH_3COONa at infinite dilution are 126.45, 426.16 and 91.0 S cm^2 mol^-1 respectively. The molar conductance of CH_3COOH at infinite dilution is. Choose the right option for your answer.

1. 201.28 S cm\(^2\) mol\(^{-1}\)

2. 390.71 S cm\(^2\) mol\(^{-1}\)

3. 698.28 S cm\(^2\) mol\(^{-1}\)

4. 540.48 S cm\(^2\) mol\(^{-1}\)

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Answer: 2. 390.71 S cm\(^2\) mol\(^{-1}\)

Key idea: Kohlrausch's law of independent migration of ions.

\(\Lambda^\circ(\mathrm{CH_3COOH})=\Lambda^\circ(\mathrm{CH_3COONa})+\Lambda^\circ(\mathrm{HCl})-\Lambda^\circ(\mathrm{NaCl})\)

\(=91.0+426.16-126.45=390.71\ \mathrm{S\,cm^2\,mol^{-1}}\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The molar conductance of NaCl, HCl and CH_3COONa at infinite dilution are 126.45, 426.16 and 91.0 S cm^2 mol^-1 respectively. The molar conductance of CH_3COOH at infinite dilution is. Choose the right option for your answer.

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