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Answer: 4. \(Fe^{2+}, Mn^{2+}\)

Key idea: iso-electronic species have the same number of electrons.

  • \(\mathrm{O^{2-}}\) (10) and \(\mathrm{F^-}\) (10): yes
  • \(\mathrm{Na^+}\) (10) and \(\mathrm{Mg^{2+}}\) (10): yes
  • \(\mathrm{Mn^{2+}}\) (23) and \(\mathrm{Fe^{3+}}\) (23): yes
  • \(\mathrm{Fe^{2+}}\) (24) and \(\mathrm{Mn^{2+}}\) (23): no

So option 4 is not an iso-electronic pair.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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