1. 1 : 2 2. 1 : 1 3. √(2) : 1 4. 1 : √(2)

Answer: 4. 1 : √(2) Speed of a transverse wave on a string is v=√(T/μ) , so v∝sqrt T . v_i/v_f=√(T/2T)=1/sqrt2 , i.e. 1:sqrt2 . Option (4) is correct.

Topic: Wave motion: longitudinal and transverse waves, wave speed· Oscillations and Waves

If the initial tension on a stretched string is doubled, then the ratio of the initial and final speeds of a transverse wave along the string is :

1. 1 : 2

2. 1 : 1

3. \(\sqrt{2}\) : 1

4. 1 : \(\sqrt{2}\)

Doubtly Asked 30 Oct 2026 NEET UG 2022 Practice test neet Save WhatsApp Report

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Answer: 4. 1 : \(\sqrt{2}\)

Speed of a transverse wave on a string is \(v=\sqrt{T/\mu}\), so \(v\propto\sqrt T\).

\(\dfrac{v_i}{v_f}=\sqrt{\dfrac{T}{2T}}=\dfrac{1}{\sqrt2}\), i.e. \(1:\sqrt2\).

Option (4) is correct.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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If the initial tension on a stretched string is doubled, then the ratio of the initial and final speeds of a transverse wave along the string is :

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