1. 5 m 2. 10/3 m 3. 20/3 m 4. 10 m

Answer: 3. 20/3 m Place the 10 kg mass at the origin and the 20 kg mass at 10 m. x_cm=10(0)+20(10)/10+20=200/30=20/3\ m The centre of mass lies closer to the heavier mass, so it is 20/3 m from the 10 kg mass. Option (3).

Topic: Centre of mass of two-particle system and rigid body· Rotational Motion

Two objects of mass 10 kg and 20 kg respectively are connected to the two ends of a rigid rod of length 10 m with negligible mass. The distance of the center of mass of the system from the 10 kg mass is :

1. 5 m

2. \(\frac{10}{3}\) m

3. \(\frac{20}{3}\) m

4. 10 m

Doubtly Asked 30 Oct 2026 NEET UG 2022 Practice test neet Save WhatsApp Report

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Answer: 3. \(\frac{20}{3}\) m

Place the 10 kg mass at the origin and the 20 kg mass at 10 m.

\(x_{cm}=\dfrac{10(0)+20(10)}{10+20}=\dfrac{200}{30}=\dfrac{20}{3}\ \text{m}\)

The centre of mass lies closer to the heavier mass, so it is \(20/3\) m from the 10 kg mass. Option (3).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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Two objects of mass 10 kg and 20 kg respectively are connected to the two ends of a rigid rod of length 10 m with negligible mass. The distance of the center of mass of the system from the 10 kg mass is :

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