1. 5.6 m ³ 2. 5.6 × 10⁶ m ³ 3. 5.6 × 10³ m ³ 4. 5.6 × 10⁻³ m ³

The volume occupied by the molecules contained in 4.5 kg water at STP, if the intermolecular forces vanish away is :

1. 5.6 m\(^3\)

2. \(5.6 \times 10^{6}\) m\(^3\)

3. \(5.6 \times 10^{3}\) m\(^3\)

4. \(5.6 \times 10^{-3}\) m\(^3\)

Doubtly Asked 30 Oct 2026 NEET UG 2022 Practice test neet Save WhatsApp Report

Best answer

Answer: 1. 5.6 m\(^3\)

With intermolecular forces gone, the water molecules behave like an ideal gas, and one mole occupies 22.4 L at STP.

Moles \(=\dfrac{4500\ \text{g}}{18\ \text{g/mol}}=250\).

\(V=250\times22.4\ \text{L}=5600\ \text{L}=5.6\ \text{m}^3\). Option (1).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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