1. -20Gm/R 2. -8Gm/R 3. -12Gm/R 4. -16Gm/R

Answer: 4. -16Gm/R Find the point where the net field is zero, then add the potentials of both masses there. Let the point be at distance x from m : Gm/x²=G 9m/(R-x)²⇒ R-x=3x⇒ x=R/4 . Distance from 9m is 3R/4 . V=-Gm/R/4-9Gm/3R/4=-4Gm/R-12Gm/R=-16Gm/R . The answer is -16Gm/R .

Topic: Gravitational potential energy and gravitational potential· Gravitation

Two bodies of mass m and 9m are placed at a distance R. The gravitational potential on the line joining the bodies where the gravitational field equals zero, will be (G = gravitational constant) :

1. \(-\frac{20Gm}{R}\)

2. \(-\frac{8Gm}{R}\)

3. \(-\frac{12Gm}{R}\)

4. \(-\frac{16Gm}{R}\)

Doubtly Asked 30 Oct 2026 NEET UG 2023 Practice test neet Save WhatsApp Report

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Answer: 4. \(-\frac{16Gm}{R}\)

Find the point where the net field is zero, then add the potentials of both masses there.

Let the point be at distance \(x\) from \(m\): \(\dfrac{Gm}{x^2}=\dfrac{G\,9m}{(R-x)^2}\Rightarrow R-x=3x\Rightarrow x=\dfrac R4\).
Distance from \(9m\) is \(\dfrac{3R}{4}\).
\(V=-\dfrac{Gm}{R/4}-\dfrac{9Gm}{3R/4}=-\dfrac{4Gm}{R}-\dfrac{12Gm}{R}=-\dfrac{16Gm}{R}\).

The answer is \(-16Gm/R\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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Two bodies of mass m and 9m are placed at a distance R. The gravitational potential on the line joining the bodies where the gravitational field equals zero, will be (G = gravitational constant) :

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