1. 50 mathrmm s⁻² 2. 1.2 mathrmm s⁻² 3. 150 mathrmm s⁻² 4. 1.5 mathrmm s⁻²

Calculate the maximum acceleration of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is 0.15 (g=10 m s^-2).

1. \(50\,\mathrm{m\,s^{-2}}\)

2. \(1.2\,\mathrm{m\,s^{-2}}\)

3. \(150\,\mathrm{m\,s^{-2}}\)

4. \(1.5\,\mathrm{m\,s^{-2}}\)

Doubtly Asked 30 Oct 2026 NEET UG 2023 Practice test neet Save WhatsApp Report

Best answer

Answer: 4. \(1.5\,\mathrm{m\,s^{-2}}\)

The body stays at rest relative to the car only while the pseudo-force \(ma\) is balanced by static friction, whose maximum is \(\mu mg\).

\(ma_{max}=\mu mg\Rightarrow a_{max}=\mu g=0.15\times10=1.5\ \mathrm{m\,s^{-2}}\).

The answer is 1.5 m s^-2.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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