For a certain reaction, the rate = k[A]^2[B], when the initial concentration of A is tripled keeping concentration of B constant, the initial rate would

1. increase by a factor of three.

2. decrease by a factor of nine.

3. increase by a factor of six.

4. increase by a factor of nine.

Doubtly Asked 30 Oct 2026 NEET UG 2023 Practice test neet Save WhatsApp Report

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Answer: 4. increase by a factor of nine.

Key idea: Rate is proportional to \([A]^2\) when B is constant.

New rate = \(k(3[A])^2[B] = 9k[A]^2[B]\), so the rate increases by a factor of 9. Option 4.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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