In the above diagram, a strong bar magnet is moving towards solenoid-2 from solenoid-1. The direction of induced current in solenoid-1 and that in solenoid-2, respectively, are through the directions:

Question

In the above diagram, a strong bar magnet is moving towards solenoid-2 from solenoid-1. The direction of induced current in solenoid-1 and that in solenoid-2, respectively, are through the directions: 1. BA and DC 2. AB and DC 3. BA and CD 4. AB and CD

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Answer: 2. AB and DC Key idea: Lenz's law: the induced current opposes the change in flux, so a solenoid end facing a moving magnet behaves like a pole that resists the motion. Solenoid-1: the N pole is moving away from it, so the induced field tries to attract it, and the end facing the magnet acts as a S pole. This fixes the current direction as A→ B . Solenoid-2: the S pole of the magnet is approaching, so the end facing the magnet must act as a S pole to repel it. Because of the winding sense, this gives current D→ C . Option 2 (AB and DC).

In the above diagram, a strong bar magnet is moving towards solenoid-2 from solenoid-1. The direction of induced current in solenoid-1 and that in solenoid-2, respectively, are through the directions:

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