Topic: Capacitors, series and parallel combination, parallel plate capacitor with/without dielectric· Electrostatics

In the following circuit, the equivalent capacitance between terminal A and terminal B is :

In the following circuit, the equivalent capacitance between terminal \(A\) and terminal \(B\) is :

capacitor network of five 2 microF capacitors between A and B

1. 4 \(\mu F\)

2. 2 \(\mu F\)

3. 1 \(\mu F\)

4. 0.5 \(\mu F\)

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Answer: 2. 2 \(\mu F\)

Key idea: The circuit is symmetric, so the middle capacitor is part of a balanced bridge and holds no charge.

Let M be the junction between the two upper capacitors and N the junction between the two lower ones. The top path and bottom path are identical, so M and N are at the same potential and the middle \(2\ \mu F\) capacitor can be ignored.

Each path has two \(2\ \mu F\) capacitors in series: \(\frac{2\times2}{2+2}=1\ \mu F\).
The two paths are in parallel: \(1+1=2\ \mu F\).

Option 2.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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In the following circuit, the equivalent capacitance between terminal A and terminal B is :

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