1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to

1. 200 mg

2. 750 mg

3. 250 mg

4. Zero mg

Doubtly Asked 30 Oct 2026 NEET UG 2024 Practice test neet Save WhatsApp Report

1 answer

Best answer

Answer: 3. 250 mg

Key idea: find the limiting reagent for \(\mathrm{NaOH+HCl\to NaCl+H_2O}\).

NaOH: \(1/40=0.025\) mol = 25 mmol. HCl: \(25\times0.75=18.75\) mmol.

Left NaOH = \(25-18.75=6.25\) mmol \(\times40=250\) mg. Option 3.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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