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Answer: 1. \(BaCl_2 + Na_2SO_4 \rightarrow BaSO_4 + 2NaCl\)

Key idea: a redox reaction has a change in oxidation numbers.

\(\mathrm{BaCl_2+Na_2SO_4\to BaSO_4+2NaCl}\) is a double displacement (precipitation) with no oxidation number change. The others: Zn 0 to +2, Cl in \(\mathrm{KClO_3}\) +5 to 0, \(\mathrm{H_2}\) 0 to +1. Option 1.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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