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Answer: 2. B and D only

Key idea: \(\mu=\sqrt{n(n+2)}\) BM, so equal unpaired electrons give equal moment.

  • \(\mathrm{Ti^{3+}}\) (\(d^1\)): 1
  • \(\mathrm{Cr^{2+}}\) (\(d^4\)): 4
  • \(\mathrm{Mn^{2+}}\) (\(d^5\)): 5
  • \(\mathrm{Fe^{2+}}\) (\(d^6\)): 4
  • \(\mathrm{Sc^{3+}}\) (\(d^0\)): 0

B and D both have 4 unpaired electrons (4.90 BM). Option 2.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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