1. ABC₄ 2. A₂BC₂ 3. ABC₃ 4. AB₂C₂

A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is :(Given atomic masses of A = 64; B = 40; C = 32 u)

1. \(ABC_4\)

2. \(A_2BC_2\)

3. \(ABC_3\)

4. \(AB_2C_2\)

Doubtly Asked 30 Oct 2026 NEET UG 2024 Practice test neet Save WhatsApp Report

Best answer

Answer: 3. \(ABC_3\)

Key idea: empirical formula from percentage: divide by atomic mass, then by the smallest value.

C% = 100 - 32 - 20 = 48.

Formula \(\mathrm{ABC_3}\): option 3.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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