Topic: Newton's laws, force and inertia, momentum, impulse· Laws of Motion

A ball of mass 0.5 kg is dropped from a height of 40 m. The ball hits the ground and rises to a height of 10 m. The impulse imparted to the ball during its collision with the ground is (Take g = 9.8 m/s^2)

1. 21 NS

2. 7 NS

3. 0

4. 84 NS

Doubtly Asked 30 Oct 2026 NEET UG 2025 Practice test neet Save WhatsApp Report

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Answer: 1. 21 NS

Key idea: impulse equals change in momentum, and the velocity direction reverses at the ground.

$$v_{\text{before}}=\sqrt{2gh_1}=\sqrt{2\times9.8\times40}=28\ \mathrm{m/s}\ (\text{down})$$$$v_{\text{after}}=\sqrt{2gh_2}=\sqrt{2\times9.8\times10}=14\ \mathrm{m/s}\ (\text{up})$$$$J=m(v_{\text{after}}-(-v_{\text{before}}))=0.5\times(14+28)=21\ \mathrm{N\,s}$$

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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A ball of mass 0.5 kg is dropped from a height of 40 m. The ball hits the ground and rises to a height of 10 m. The impulse imparted to the ball during its collision with the ground is (Take g = 9.8 m/s^2)

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