Skip to content
doubtly

1 answer

Best answer

Answer: 4. 108 days

Key idea: no external torque, so angular momentum \(L=I\omega\) is conserved.

For a uniform sphere, \(I=\tfrac25MR^2\). Mass stays the same, and with \(R\to2R\), \(I\to4I\). Then \(\omega\to\omega/4\), so the period becomes 4 times larger:

$$T'=4\times27=108\ \text{days}$$
Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.