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Topic: Relative velocity· Kinematics

Two cities X and Y are connected by a regular bus service with a bus leaving in either direction every T min. A girl is driving scooty with a speed of 60 km/h in the direction X to Y notices that a bus goes past her every 30 minutes in the direction…

Two cities X and Y are connected by a regular bus service with a bus leaving in either direction every T min. A girl is driving scooty with a speed of 60 km/h in the direction X to Y notices that a bus goes past her every 30 minutes in the direction of her motion, and every 10 minutes in the opposite direction. Choose the correct option for the period T of the bus service and the speed (assumed constant) of the buses.

1. 9 min, 40 km/h

2. 25 min, 100 km/h

3. 10 min, 90 km/h

4. 15 min, 120 km/h

1 answer

Best answer

Answer: 4. 15 min, 120 km/h

Key idea: buses in one direction are spaced \(vT\) apart. The girl meets them at the rate set by the relative speed.

Let bus speed be \(v\) km/h, girl's speed 60 km/h. Same direction: the gap is covered at relative speed \(v-60\) in 30 min; opposite direction: relative speed \(v+60\) in 10 min.

$$\text{spacing}=vT=(v-60)\times30=(v+60)\times10\ \ (\text{same time unit})$$$$30v-1800=10v+600\Rightarrow v=120\ \mathrm{km/h}$$

Spacing \(=(v+60)\times\tfrac{10}{60}=180\times\tfrac16=30\) km, so \(T=\dfrac{30}{120}\ \mathrm h=15\) min.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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