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Answer: \(3\pi\) cm (about 9.42 cm)

The area of a sector is related to its arc length \(l\) by

\[A = \frac{1}{2}\,r\,l\]

Substituting \(A = 54\pi\ \mathrm{cm^2}\) and \(r = 36\) cm:

\[54\pi = \frac{1}{2}\times36\times l = 18\,l\]

\[l = \frac{54\pi}{18} = 3\pi\ \text{cm} \approx 9.42\ \text{cm}\]

Check using the angle: \(\dfrac{\theta}{360^\circ}\times\pi(36)^{2} = 54\pi\) gives \(\theta = 15^\circ\), and then \(l = \dfrac{15}{360}\times2\pi\times36 = 3\pi\) cm.

Doubtly AI · 23 Oct 2026 AI-verified · Oct 2026 Report
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