Question

What is the angular momentum of the electron in the third Bohr orbit in the hydrogen atom? (h/2π =1.055 × 10^-34 kg m² / s)

a) 3.165 × 10^-34 kg m² / s

b) 3.165 × 10³⁴ kg m² / s

c) 3.165 × 10^-24 kg m² / s

d) 3.165 × 10²⁴ kg m² / s

 

Answer 1

 

Angular momentum of an electron in the nth Bohr orbit of hydrogen atom L=$\frac{nh}{2\pi }$

For n=3

$L=\frac{3h}{2\pi }$

$L=3\times 1.055\times {10}^{-34}$

L=3.165 $\times {10}^{-34}Kg{m}^2/s$

a)option is correct