Chapter: Random· Chemistry

The oxidation state of Fe in the brown ring complex [Fe(H2O)5NO]SO4 is:(a) + 1 (b) + 2 (c) + 3 (d) + 4

The oxidation state of Fe in the brown ring complex [Fe(H₂O)₅NO]SO₄ is:

(a) + 1

(b) + 2

(d) + 4

Doubtly Asked 9 Apr 2021 Student doubt jeemain Save WhatsApp Report

1 answer

Best answer

Corret option is a) +1

Explaination ::
[Fe(H₂O)₅NO]SO_{4 \(\rightarrow ([Fe(H_2O)_5NO] )^{+2}+(SO_4)^{-2}\)}

\((fe^+)^{+1} =+2\)

charge on fe= +1

Doubtly · 9 Apr 2021 Report

Was this answer helpful?