The perimeter of a rectangle is 40 cm and its length is 5 cm more than twice its breadth. Find the length and the

Let's solve the problem step by step:

Let the breadth of the rectangle be 'x' cm, and the length be 'y' cm.

Given information:

• The perimeter of a rectangle is 40 cm: 2(x + y) = 40.
• The length is 5 cm more than twice the breadth: y = 2x + 5.

We can form two equations based on the given information:

Equation 1: 2(x + y) = 40 Equation 2: y = 2x + 5

Substitute y = 2x + 5 into Equation 1: 2(x + (2x + 5)) = 40

Simplify the equation: 2(3x + 5) = 40

Distribute 2 into the parentheses: 6x + 10 = 40

Subtract 10 from both sides of the equation: 6x = 40 - 10

Simplify: 6x = 30

Divide both sides of the equation by 6: x = 30 / 6

Simplify: x = 5

Substitute x = 5 into Equation 2 to find the value of y: y = 2(5) + 5

Simplify: y = 10 + 5

y = 15

Therefore, the length of the rectangle is 15 cm, and the breadth is 5 cm.