Question

Calculate the ratio of mean square speeds of molecules of a gas at 30 K and 120 K. 

Answer 1

Given : T₁ = 30K, T₂= 120K

The mean square speed v² = \(\frac{3RT}{M_o}\)

∴ \(\frac{v_1^2}{v_2^2} =\frac{T_1}{T_2}\) for given gas

∴ \(\frac{v_1^2}{v_2^2} =\frac{30K}{120K}\) = \(\frac14\)

\(\frac14\) is the ratio