Chapter: Oscillations· Physics

The total energy of a body of mass 2 kg performing S.H.M. is 40 J. Find its speed while crossing the centre of the path.

The total energy of a body of mass 2 kg performing S.H.M. is 40 J. Find its speed while crossing the centre of the path.

Neha P. Asked 31 May 2022 Student doubt Save WhatsApp Report

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Best answer

Given : m = 2 kg, E = 40 J

The speed of the body while crossing the centre of the path (mean position) is v_max and the total energy is entirely kinetic energy.

\(\frac{1}{2}\)mv²_max = E

∴ v_max = \(\sqrt{\frac{2E}{m}}= \sqrt{\frac{2×40}{2}}\) = 6.324 m/s

Neha P. · 31 May 2022 Report

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