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Answer: in a medium with charge density \(\rho\) and current density \(\vec J\), Maxwell's equations in differential form are \(\nabla\cdot\vec D = \rho\), \(\nabla\cdot\vec B = 0\), \(\nabla\times\vec E = -\partial\vec B/\partial t\) and \(\nabla\times\vec H = \vec J + \partial\vec D/\partial t\).

  1. Gauss's law for electricity: \[\nabla\cdot\vec D = \rho\]
  2. Gauss's law for magnetism: \[\nabla\cdot\vec B = 0\]
  3. Faraday's law: \[\nabla\times\vec E = -\frac{\partial\vec B}{\partial t}\]
  4. Ampère–Maxwell law: \[\nabla\times\vec H = \vec J + \frac{\partial\vec D}{\partial t}\]

For a linear, isotropic medium the fields are related by the constitutive relations

\[\vec D = \varepsilon\vec E,\quad \vec B = \mu\vec H,\quad \vec J = \sigma\vec E\]

where \(\varepsilon = \varepsilon_0\varepsilon_r\) is the permittivity, \(\mu = \mu_0\mu_r\) the permeability and \(\sigma\) the conductivity of the medium. The term \(\partial\vec D/\partial t\) is the displacement current density. In free space (\(\rho = 0\), \(\vec J = 0\), \(\varepsilon = \varepsilon_0\), \(\mu = \mu_0\)) these reduce to the source-free equations that give electromagnetic waves travelling at \(c\).

Doubtly AI · 23 Oct 2026 AI-verified · Oct 2026 Report
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