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Suppose you have taken a dilute solution of oleic acid in such a way that its concentration becomes 0.01 cm3 of oleic acid per cm3 of the solution. Then you make a thin film of this solution (monomolecular thickness) of area 4 cm2 by considering 100 spherical drops of radius \((\frac{3}{40\pi})^{\frac 13}\times10^{-3}\) cm. Then the thickness of oleic acid layer will be x × 10–14 m.

Where x is1...........

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correct Answer is 25
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