The electric field in a region is given by vec E=2/5E₀hat i+3/5 E₀hat j with E0 = 4.0 × 10³ N/C .The flux of this field through a rectangular surface area 0.4 m² parallel to the Y – Z plane is..........Nm²C^(–1).

Answer is 640 ɸ = Ex A ⇒ 2/5 x 4 x 103 x 0.4 = 640

The electric field in a region is given by with vector E = 2/5 E0 i + 3/5 E0 j with E0 = 4.0 × 10^3 N/C

The electric field in a region is given by \(\vec E=\frac 25E_0\hat i+\frac35 E_0\hat j\) with E0 = 4.0 × 10³ \(\frac NC\) .The flux of this field through a rectangular surface area 0.4 m² parallel to the Y – Z plane is..........Nm²C^–1.

Mr C. Asked 20 Jun 2022 Student doubt Save WhatsApp Report

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Answer is 640

ɸ = Ex A

⇒ \(\frac 25\) x 4 x 103 x 0.4

= 640

Mr C. · 20 Jun 2022 Report

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​ The electric field in a region is given by with vector E = 2/5 E0 i + 3/5 E0 j with E0 = 4.0 × 10^3 N/C

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The electric field in a region is given by with vector E = 2/5 E0 i + 3/5 E0 j with E0 = 4.0 × 10^3 N/C